Robredo to meet Anderson for Casablanca crown

Updated: April 13, 2013


Tommy Robredo of Spain and South
Africa’s Kevin Anderson were semifinal winners Saturday and will meet for the
title at the Moroccan Grand Prix.

Robredo rebounded from a very sluggish start to earn a 1-6, 6-3, 6-2 victory
over top-seeded Stanislas Wawrinka of Switzerland, while the second-seeded
Anderson followed with a similar result by rallying for a 2-6, 6-4, 6-2
triumph over Martin Klizan of Slovakia.

Wawrinka raced out to a 5-0 lead in the first semifinal, but the 2010
Casablanca champ was unable to sustain the momentum. Robredo regrouped in the
second set and broke serve twice before dominating the third set with a trio
of breaks.

The 72nd-ranked Robredo improved to 5-1 lifetime against Wawrinka and also
reached the Casablanca final for the second time. He lost to Guillermo Canas
back in 2001.

Robredo will be trying for his 11th overall ATP World Tour title and 10th on
clay. He hasn’t won a tournament since capturing the Santiago crown in
February 2011 and owns a career record of 10-7 in finals.

Anderson is 2-2 all-time in title matches, including a loss to Bernard Tomic
in the Sydney season-opener this year. His last title came in March 2012 in
Delray Beach. He will play in a tour-level final on clay for the first time.

Robredo, who is working his way back from a leg injury that sidelined him for
five months last year, has never played Anderson.

Sunday’s winner will earn $96,000.